| 0){
$sql = mysql_query("SELECT COUNT(*) AS total_pages FROM {$prefix}pages WHERE category = $c AND accepted = 'y'");
$total_pages = mysql_result($sql,0,"total_pages");
$k = 1; // номер первой записи на рассматриваемой странице
$count_y[$k] = 0;
$sql = mysql_query("SELECT url, title, description, accepted FROM {$prefix}pages WHERE category = $c ORDER BY id");
for ($x = 0; $x < $all_pages; $x++){
if ($x == $k us |
 |
|